Only by contending with challenges that seem to be beyond your strength to handle at the moment you can grow more surely toward the stars.

Depth-First Search is one of the fundamental algorithms in graph theory. It's a must to know!

Nowadays it's a piece of cake, but I did struggle a bit to get my head around this and other graph theory algorithms.

## Common ways to represent graphs in a computer

The most common representations for graphs are Adjacency matrix and Adjacency list.

` ````
#include <iostream>
#include <cstdlib>
using namespace std;
// The maximum number of nodes in the graph.
// If this number is not known beforhand, dynamic allocation is a better idea.
const int N = 10;
/*
* Perform a Depth-First Search.
* Nodes are identified by integers from 0 to n - 1.
*
* graph[u][v] is true if node u and v are connected, false otherwise.
*/
void dfs(int u, bool graph[][N], bool visited[], int n) {
// Mark node u to avoid entering in an infinite loop.
visited[u] = true;
// Do something with u, e.g., print it out.
cout << u << " ";
// Visit each adjacent node of u.
for (int v = 0; v < n; v++) {
if (graph[u][v] && !visited[v]) {
dfs(v, graph, visited, n);
}
}
// This step is optional, unmark u if you want to travel all the possible
// tours, otherwise leave it marked.
//visited[u] = false;
}
int main() {
bool graph[N][N];
bool visited[N];
// A common way to express graphs is by specifiying the number for nodes n,
// and the number of edges m.
int n, m;
cin >> n >> m;
for (int i = 0; i < n; i++) {
for (int j = 0; j < m; j++) {
graph[i][j] = false;
}
}
for (int i = 0; i < m; i++) {
int u, v;
cin >> u >> v;
// An undirected graph.
graph[u][v] = true;
graph[v][u] = true;
}
for (int i = 0; i < n; i++) {
visited[i] = false;
}
for (int u = 0; u < n; u++) {
if (!visited[u]) {
dfs(u, graph, visited, n);
}
}
return 0;
}
```

` ````
5 4
0 1
0 2
2 3
2 4
```

` ````
0 1 2 3 4
```

` ````
#include <iostream>
#include <cstdlib>
#include <vector>
using namespace std;
// The maximum number of nodes in the graph.
// If this number is not known beforhand, dynamic allocation is a better idea.
const int N = 10;
/*
* Perform a Depth-First Search.
* Nodes are identified by integers from 0 to n - 1.
*
* graph[u] contains v if node v is a neighbor of u.
*/
void dfs(int u, vector<int> graph[], bool visited[]) {
// Mark node u to avoid entering in an infinite loop.
visited[u] = true;
// Do something with u, e.g., print it out.
cout << u << " ";
// Visit each adjacent node of u.
for (int v : graph[u]) {
if (!visited[v]) {
dfs(v, graph, visited);
}
}
// This step is optional, unmark u if you want to travel all the possible
// tours, otherwise leave it marked.
//visited[u] = false;
}
int main() {
vector<int> graph[N];
bool visited[N];
// A common way to express graphs is by specifiying the number for nodes n,
// and the number of edges m.
int n, m;
cin >> n >> m;
for (int i = 0; i < m; i++) {
int u, v;
cin >> u >> v;
// An undirected graph.
graph[u].push_back(v);
graph[v].push_back(u);
}
for (int i = 0; i < n; i++) {
visited[i] = false;
}
for (int u = 0; u < n; u++) {
if (!visited[u]) {
dfs(u, graph, visited);
}
}
return 0;
}
```